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psyam 5 posts Joined 02/08
16 Jul 2009
small SQl query

I have a table with dataColumn 1 Column 2A 1A 2A 3B 1B 2 C 4c 6c 7i need to get the output as (based on group by first column)A 1 2 3B 1 2C 4 6 7Please let me know the SQL to achieve this

sk73 52 posts Joined 07/09
22 Jul 2009

hi ...I tried out this in MS-Access. The query came out as below:TRANSFORM Max(Table.Col2) AS MaxOfCol2SELECT Table.Col1 AS [COL1]FROM [Table]GROUP BY Table.Col1PIVOT Table.Col2;I am not familiar with the in-built functions of Teradata's SQL. Basically, I am learning it. I feel I will become familiar with it day-by-day.I am not sure about the answer. Please, send me a message if you find an answer. Thanks...Regards,SK

Jimm 298 posts Joined 09/07
23 Jul 2009

Teradata does not have a Transform or Pivot function - they are regarded as presentation level functions and it relies on the presentation tool (Cognos/ Access/ BO/ etc) to do that.The SQL below will Pivot up to 10 columns. It also give you a column which tells you whether you have enough columns! You can extend it if you want more, but you have to have a finite maximum number of columns.This returns Null for empty columns, but you can easily change this.SelectId, Max(CASE WHEN PosN = 1 THEN Col2 END) As Val1, Max(CASE WHEN PosN = 2 THEN Col2 END) As Val2, Max(CASE WHEN PosN = 3 THEN Col2 END) As Val3, Max(CASE WHEN PosN = 4 THEN Col2 END) As Val4, Max(CASE WHEN PosN = 5 THEN Col2 END) As Val5, Max(CASE WHEN PosN = 6 THEN Col2 END) As Val6, Max(CASE WHEN PosN = 7 THEN Col2 END) As Val7, Max(CASE WHEN PosN = 8 THEN Col2 END) As Val8, Max(CASE WHEN PosN = 9 THEN Col2 END) As Val9, Max(CASE WHEN PosN = 10 THEN Col2 END) As Val10, Max(CASE WHEN PosN > 10 THEN 'You Need More Columns!' Else '' END) As CheckValFrom (Select Col1 , Col2 , Row_Number () Over (Partition By Col1 Order By Col2) as PosNFrom tbl_with_data) As D1Group By 1;

sk73 52 posts Joined 07/09
23 Jul 2009

thank you Jim!!!Great information too.

24 Jul 2009

we can also try with Recursive SQLrefer to the below link

sk73 52 posts Joined 07/09
24 Jul 2009

Hi Rahul,Thank you.I am on my way to figure out some thing from there.

sk73 52 posts Joined 07/09
29 Jul 2009

hi...I used the following procedure:1. Count the number of records2. Create a new table with columns equal to (count-1)3. Access the original table's recordset and place it into the newly created table only if the original table's values is not null.I could not write a query though.

eejimkos 73 posts Joined 01/12
29 Jul 2012


the solution is either Recursive sql  or with serial left join on the column that you want to have all the rows from your chain.



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